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I need to know the answer to this question, but further more I would like to know how you went about getting that answer. Thanks!


(Complex Numbers)
1. For i = , if 3i (2 + 5i) = x + 6i, then x = ?
A. –15
B. 5
C. 5i
D. 15i
E. 27i

2006-06-26 14:56:02 · 4 answers · asked by lonelyinChicago 1 in Education & Reference Higher Education (University +)

4 answers

Distribute the 3i on the left
3i (2 + 5i) = x + 6i
6i + 15i^2 = x + 6i
Remember that i^2 = -1, so
6i + (15)(-1) = x + 6i
6i - 15 = x + 6i
Now subtract 6i from both sides
-15 = x
So the answer must be "A"

2006-06-26 15:07:24 · answer #1 · answered by tdw 4 · 0 0

this is easy. step one . 3i x 2 = 6i , and 3i x 5i = -15 because i x i = -1 so u get 6i - 15 = x + 6i . subtract 6i from both side , you get x= -15.

u just need to know (i x i = -1)

2006-06-26 16:10:32 · answer #2 · answered by VAN C 1 · 0 0

3i (2+5i) = x + 6i

1. Subtract 6i from each side: 3i (2+5i) -6i = x

2. Multiply out the parentheses: 3i x 2= 6i and 3i x 5i= 15i, so you have
6i + 15i - 6i = x

3. Adding and subracting all the i's gets 15i = x

2006-06-26 15:05:36 · answer #3 · answered by Farly the Seer 5 · 0 0

A. -15

3i (2 + 5i) = x + 6i
6i + 15(i * i) = x + 6i
6i - 15 = x + 6i
-15 = x

2006-06-26 15:00:02 · answer #4 · answered by Anonymous · 0 0

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