If a ball weighing 25 pounds and moving at 5 miles per hour hit a ball weighing 100 pounds and standing....?

Question

still how much energy is transferred ?

Answer 1

ok, so if we're assuming that it was a head on elastic collision, and all the energy was transferred then there are two possible situations: if the 25lb ball was sliding then the total energy transferred will be equal to the amount it had originally (since we assumed elastic collision) that is equal to 1/2mv^2...where mass would usually be measured using the metric system.
if the ball was rolling then it has not only translational energy (1/2mv^2) but also rotational energy which is equal to 1/2Iw^2 where I = inertia of a ball...if it is a solid sphere the moment of inertia is equal to 2/5mr^2 (m = mass, r = radius) and w (omega) = rotational speed in radians per second...which is equal to velocity/radius. so the amount of energy transferred would be equal to 1/2Iw^2 + 1/2mv^2.

Answer 2

The 25-pound will probably transfer all of its energy to the 100-pound ball, making the lighter stop completely and the heavier go 1.25 mph, so that momentum is conserved. During a collision, total momentum (product of mass and velocity) is always conserved but sometimes kinetic energy can be lost. The formula for kinetic energy is 1/2 mass times velocity squared....

Answer 3

(25lb)(5mph)^2-heat-sound-1/2(25lbs)(speed of 25lb ball after collision)^2

Answer 4

come again