How do you factor the equation x^3 -64=0?

Question

please help!!

Answer 1

+64 to both sides which gives you:
x^3=64 then you take the cuibc root of each side...

answer is x=4 but i didnt tell you that

Answer 2

since there are only two terms, get one term on the other side of the equation:

x^3 - 64 = 0
x^3 - 64 + 64 = 0 + 64

x^3 + 0 = 64
x^3 = 64

Take cube roots of both sides:

x = cuberoot(64)

Use your calculator to find cuberoot(64), or try some numbers:

2*2*2 = 8
3*3*3 = 27
4*4*4 = 64

so x = 4

Answer 3

x^3-64=0
x^3=64
x=4

Answer 4

x^3-64=0 = x=4

Answer 5

Do you want to factor it or solve it? If you want to SOLVE it, you add 64 to both sides and then take the cube root of both sides. You end up with x = 4. If you want to FACTOR it, it is a difference of two cubes (x cubed is x^3, and 4 cubed is 64). The rule for this is x^3 - y^3 = (x-y)(x^2 + xy + y^2). The x in this case is x and the y in this case is 4. So you have (x-4)(x^2 + 4x + 16), which is the factored form. The 16 is the y^2, which in this case is 4^2, which is 16.

Answer 6

x^3 -64=0
(x)^3 -(4)^3 =0
(x-4)(x^2 + 4x+16)=0 { use identity x^3 -y^3 = (x-y)(x^2 +xy+y^2)}
(x-4)=0 { since x^2 +4x+16=0 is not possible as this equation does not give real values of x . As discriminat(D) = B^2 - 4 AC
= (4)^2-4X1X16
= 16-64
= -48 }
so only x-4=0 is possible
hence x=4 is only solution to above equation.

Answer 7

Factor X3 64

Answer 8

you subtract 64 from each side, which is x^3=64. Then you cube root 64, which is 4. so x=4.

Answer 9

x=4

Answer 10

In general the cube (a^3 - b^3) is factored as (a - b)(a^2 + ab + b^2).

So (x^3 - 64) = (x - 4)(x^2 + 4x + 16)

Answer 11

Triatic equation:

x^3 + 0x^2 + 0x - 64 = 0

Just making the missing x's equal to zero...