Using Algebra, I can prove to you that 1+1 does not equal 2. Can you prove me wrong? How? (A^2 is A squared)

Question

A=1
B=A
A=B
A^2=AB
A^2 - B^2 = AB - B^2
(A+B)(A-B) = B(A-B)
A+B=B
1+1=1
2=1.

No haters please.

Answer 1

A=1
B=A
A=B
A^2=AB
A^2 - B^2 = AB - B^2
(A+B)(A-B) = B(A-B)
A+B=B ( THIS STEP IS WRONG YOU CANT CANCEL A-B ON BOTH SIDES AS A=B AND A-B = 0)
1+1=1
2=1.

Answer 2

A=1
B=A
A=B
A^2=AB
A^2 - B^2 = AB - B^2
(A+B)(A-B) = B(A-B)

so (1+1)(1-1) = 1(1-1)

2(0)=1(0) there for 0=0

Only when you do math incorrectly can you get the answer you want instead of what is right.

Nice try though

Answer 3

B-A = 0

So, you cannot eliminate B-A from either side, as that would imply a zero division.

A simpler spoof is

2^0 = 1
3^0 = 1,

so, I can show that 3=2

Same fallacy, 0 does not follow some of the math properties.

Answer 4

.............
(A+B)(A-B) = B(A-B)
A+B=B

This step is wrong because since A=B, A=b equals zero, and if you divide both sides of the equation by zero then 0=0.

P.S.

[Sol] (A+B)(A-B)=B(A-B)
(2)(0)=1(0)
Left Hand Side: 2*0=0
Right Hand Side: 1*0=0
0=0, LHS=RHS

Everybody makes mistakes once in a while, so don't be ashamed!

Answer 5

The problem is in the step where you divide both sides by (A-B). Since A=B (steps 2 and 3), A-B=0, and you cannot divide by zero.

Answer 6

How original!
You divided by 0.
That's an invalid operation.
You haven't proved squat, except maybe you should have looked to see how many times this same thing has been posted this week.

Answer 7

Such a classic teaser!!! You can't divide the equation by (A-B), coz it's 0.

Division of any number by zero always leads to problems, and that's why there's a term called 'infinity', defined as any number divided by zero.

Answer 8

Division by 0 is not allowed, brush up on your algebra.

Answer 9

Division by zero not allowed.

Answer 10

That's so original. We haven't seen this... what 8 times today?