No
f(3+1)=f(4)=2(4)+1=9
but
f(3) + f(1)= [2(3)+1] + [2(1)+1] = 7 + 3 = 10
2006-06-26 03:48:35
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answer #1
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answered by QuestionAnswer 2
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f(x) = 2x + 1
f(4) = 2(4) + 1 = 8 + 1 = 9
f(3) = 2(3) + 1 = 6 + 1 = 7
f(1) = 2(1) + 1 = 2 + 1 = 3
f(3) + f(1) = 7 + 3 = 10
so f(3 + 1) does not equal f(3) + f(1)
2006-06-26 05:46:41
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answer #2
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answered by Sherman81 6
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check it out
F(3 + 1) = F (4) = 2 x 4 +1 = 9
and F(3) = 2 x 3 +1 = 7
F(1) = 2 x 1 + 1 = 3
so F(3) + F(1) = 10
therefore no
2006-06-26 03:48:57
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answer #3
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answered by dhaval70 2
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No.
y= f(x+1) Is not the same as y=f(x) + 1
2006-06-26 04:19:22
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answer #4
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answered by msmaterial 1
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Now they are not equal. The first one is 9 and the second one is 10
2006-06-26 03:50:10
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answer #5
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answered by Katie 3
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no
this function is not linear transformation as f(x+y)=2(x+y)+1=2x+2y+1 whis is not equal to f(x)+f(y)
2006-06-26 03:51:26
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answer #6
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answered by s topology 1
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if,
x=a+b then,
f(a+b)=2(a+b)+1
but f(a)=2(a)+1&f(b)=2(b)+1
so,f(a)+f(b)=2(a+b)+2,ie not equals f(a+b)
2006-06-26 05:12:19
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answer #7
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answered by Sayom 2
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nope
f(a+b)=2(a+b)+1
f(a+b)=2a+2b+1
f(a)+f(b)=2a+1+2b+1
f(a)+f(b)=2a+2b+2
f(a)+f(b)=f(a+b)+1
so not equal
2006-06-26 03:51:16
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answer #8
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answered by pareshmasade 2
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no its not
2006-06-26 03:50:39
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answer #9
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answered by abhishek b 1
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No..
2006-06-26 04:33:07
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answer #10
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answered by david 2
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