2006-06-26 03:24:08 · 27 answers · asked by hongkonghusain 2 in Dining Out ➔ Other - Dining Out
krispy kremes
2006-06-26 03:27:48 · answer #1 · answered by a8enyne 3 · 0⤊ 0⤋
It depends on what you're getting there. If you have any desire to add coffee to your donut/bagel/breakfast order, it has to be Dunkin Donuts. If you are looking for something other than a heavily glazed donut, the answer again is Dunkin Donuts. Krispy Kreme does some donuts very well but that is it. Identify what you want and make the decision based on that. One of the beauties of living in the US is that we have options, it doesn't have to one or the other, it can be based on wants and desires.
2006-06-26 11:54:27 · answer #2 · answered by JCLPRO 1 · 0⤊ 0⤋
Krispy Kream Of Course
2006-06-26 10:34:24 · answer #3 · answered by coolgirl_jlt 1 · 0⤊ 0⤋
I'm from Winston-Salem where Krispy Kreme started, there is NOTHING that cam compare to a KK donut fresh and hot. Melts in your mouth and is almost better than sex.
2006-07-02 07:56:14 · answer #4 · answered by Jen 1 · 0⤊ 0⤋
Hmmm... I just love donuts, so I'm not sure. Krispy Kreme are delicious and light and fluffy, but I think Dunkin has more variety. Ok, I'll just say it, I'm a donut slut, I love both!
2006-06-26 11:14:04 · answer #5 · answered by ndtaya 6 · 0⤊ 0⤋
I have to go with Krispy Creme. Dunkin Donuts has a larger variety, but those Krispy Creme donuts melt in your mouth. Yummy!! :>)
2006-06-26 10:59:17 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Dunkin Donuts rules
2006-06-26 10:28:33 · answer #7 · answered by ricgrif 3 · 0⤊ 0⤋
Krispykreme
2006-07-02 19:32:53 · answer #8 · answered by Jonny B 1 · 0⤊ 0⤋
Both are good but I'll go with Krispy Kreme!
2006-06-26 10:42:56 · answer #9 · answered by toyman 4 · 0⤊ 0⤋
I prefer Honeydew donuts. Or Heav'nly.
Dunkin's burns their coffee and Krispy Kreme donuts are way too greasy.
2006-06-26 10:27:53 · answer #10 · answered by Lily Iris 7 · 0⤊ 0⤋
Krispy Kreme, but only when the hotlight is on.
2006-06-26 14:03:27 · answer #11 · answered by SurferRose 4 · 0⤊ 0⤋