2006-06-25 19:16:27 · 10 answers · asked by creativeone1_98 1 in Science & Mathematics ➔ Mathematics
3(4^3+2*4^2-3*4*7+7^2-5*7+1)
do exponents first
4^3=64
4^2=16
7^2=49
now put back into the equation
3(64+2*16-3*4*7+49-35+1)
now do multiplication
2*16=32
3*4=12
12*7=84
5*7=35
so now you have 3(64+32-84+49-35+1)
now read left to right
64+32=96
96-84=12
12+49=61
61-35=26
26+1=27
3*27=81
but i could be wrong because you didn't close parentheses "()" but assuming they closed them that's what a got...it was simple because you just plug in the values for x and y and then solve using order of operations
check ya later ♥
2006-06-25 20:30:30 · answer #1 · answered by ♥ The One You Love To Hate♥ 7 · 0⤊ 0⤋
It's kind of difficult to determine the exact correct answer when you did not have the closing parentheses "()"...
However, i've listed all the possible answers with a closing ")" at several point of the expression...
But first thing first, the value of each algebraic expressions are as follows:-
~ x³ = 64
~ 2x² = 32
~ 3xy = 84
~ y² = 49
~ 5y = 35
Hence.... the possibilities...
3(x³ + 2x²) - 3xy + y² - 5y + 1 = 219
3(x³ + 2x² - 3xy) + y² - 5y + 1 = 51
3(x³ + 2x² - 3xy + y²) - 5y + 1 = 149
3(x³ + 2x² - 3xy + y² - 5y) + 1 = 79
3(x³ + 2x² - 3xy + y² - 5y + 1) = 81
hope i've been of some help.. as you can see for yourself, none of these possibilities have the answer of 128.. thus, i will advise you to re-check your workings especially the question itself..
happy calculating.. cheers... (",)
2006-06-26 04:01:52 · answer #2 · answered by Ellusive Lady 3 · 0⤊ 0⤋
you already solved X and Y, X=4, Y =7
...
But substituting x and y to: 3(x^3 + 2x^2 - 3xy + y^2 - 5y +1), this equals to 81 not 128.
3(64 + 32 - 84 + 49 - 35 + 1) = 3*27 = 81
2006-06-26 02:26:40 · answer #3 · answered by meow 3 · 0⤊ 0⤋
The question was to solve for X and Y, not the whole equation.
Because the real answer would be X=4 and Y=7...
2006-06-26 02:19:59 · answer #4 · answered by Kiri 4 · 0⤊ 0⤋
Actually, you need to solve for X and Y as it pertains to the equation, not just what they GIVE you. Of course X=4 and Y=7 . . they SAID that! You're supposed to use those values as substitutes for the X's and Y's in the equation and solve what the X and Y would be after that.
2006-06-26 02:26:31 · answer #5 · answered by TelleyJade 3 · 0⤊ 0⤋
the answer is 81 not 128
2006-06-26 04:16:56 · answer #6 · answered by sheila r 1 · 0⤊ 0⤋
x=4 y=7 and in the equation you gave, you did not close the parentheses "()". Please add more details to what you are actually trying to solve.
2006-06-26 02:55:58 · answer #7 · answered by Pickles 2 · 0⤊ 0⤋
i got 81
2006-06-26 02:21:40 · answer #8 · answered by Anonymous · 0⤊ 0⤋
i got 93
2006-06-26 02:23:48 · answer #9 · answered by woohoo 1 · 0⤊ 0⤋
No..............
2006-06-26 02:28:45 · answer #10 · answered by Anonymous · 0⤊ 0⤋