Does any math peeps here know how to solve this equation: Alpha *N(t*tilda)?

Question

diff(N(x), x) := alpha*N(t-tilda)

Answer 1

I think you are saying this:

N'(t)=A*N(t*k)

Where A, k are constants and N'(t) represents the differential, or derivative.

Problem: the constant on the inside of function N on the right hand side. If it wasn't there, this would be a nice differential equation you could solve by using introductory DE methods. I'll assume your tilda (or my "k") isn't there.

Just by looking at the problem, you can tell that the original function N(t) is an exponential form.

N'=A*N
N'/N=A
d/dt(ln(N))=A
int(d/dt(ln(N)*dt)=int(A*dt)
ln(N)=A*t + C
e^ln(N)=e^(A*t+C)
N(t)=(e^(A*t))*e^C
e^C is just a constant, I'll rename D
N(t)=D*e^(A*t)

Solved. For future reference, learn to enter a problem properly on this forum. We can't read your mind.

Answer 2

and * usually goes for multiplication.

t times Tilde?

Tilde is "~" mine is left of "1". I think everyone has one. They come in handy.

Tilde-oo (this means Bye)

OOPS
~oo

Answer 3

I don't think that is an eqation.

Notice the lack of an "equal" sign.

Answer 4

This makes no sense.
Rephrase your question

Answer 5

what?