5(x+3)-3x=2(x+8)
5x+15-3x=2x+16
0=1
equation has no solution
if you plot y=5(x+3)-3x and 2(x+8) you will see that two lines are parallel, i.e. they never cross, so no solution.
2006-06-25 16:45:44
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answer #1
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answered by Anonymous
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5(x + 3) - 3x = 2(x + 8)
Remember, multiplication distributes over addition, so
5 · x + 5 · 3 - 3x = 2 · x + 2 · 8
Simplify the multiplications first
5x + 15 - 3x = 2x + 16
Use the commutative property of addition:
5x - 3x + 15 = 2x + 16
Combine 5x - 3x = 2x
(5x - 3x) + 15 = 2x + 16
2x + 15 = 2x + 16
Transpose 2x from the right to the left and 15 from the left to the right
2x - 2x = 16 - 15
Combine the terms
0 = 1
Since you know that 0 = 1 is a false statement, you can conclude that there is no possible solution to your equation. That's all!
^_^
2006-06-25 23:15:30
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answer #2
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answered by kevin! 5
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5(x+3) -3x= 2(x+8)
5x+15-3x=2x+16
2x+15=2x+16
15=16 (which is not possible)
therefore above equation is not consistent.
2006-06-26 00:23:54
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answer #3
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answered by flori 4
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5(x + 3) - 3x = 2(x + 8)
5x + 15 - 3x = 2x + 16
2x + 15 = 2x + 16
0x = 1
x = (1/0)
This problem is unsolvable.
2006-06-25 17:12:59
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answer #4
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answered by Sherman81 6
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5(x+3)-3x=2(x+8)
5x +5*3 -3x =2x +2*8
5x+15-3x=2x+16
5x-3x-2x=16-15
0x=1
x=0
2006-06-25 18:05:15
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answer #5
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answered by loser 2
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Use distributive property. (you basically multiply the outside number by the two insides.)
5(x+3)
5x+15-3x
2x+15 is your anwer not 2x+8 someone or your mathbook incorrectly answered the problem.
2006-06-25 16:53:25
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answer #6
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answered by Anonymous
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5(x+3)-3x=2(x+8)
5x+15-3x=2x+16
2x+15=2x+16
15=16 ???
wrong question
2006-06-25 16:48:33
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answer #7
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answered by lkamh 2
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Nope, because 15 doesn't equal 16
2006-06-25 16:46:33
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answer #8
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answered by david s 4
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If 15=16,in any case,the eq. has an ans.
but now there is no????
2006-06-25 17:56:31
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answer #9
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answered by SHUBHU 2
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0=1
no solution!
2006-06-25 19:05:46
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answer #10
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answered by Sharne 2
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