If you increase the initial speed of a bullet by exactly 10%. How will the range increase in a precentage.?

Question

Air resistance can be ignored.

Answer 1

21 %

bcoz range is proportional to the square of velocity

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R prpotional to square (u)

let u0 initial velocity ,r0 inital range

u1 velocity with 10 % increase ,r1 new range

let u0=10 >>> then r0=100 (proportional to 100)

with 10% increase in velocity

u1=11 >>>> r1 =121

thus %age increase =21 %


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Answer 2

s1 = ut +1/2ft*t. u is the initial velocity, f the acceleration and t the time of flight
The new range s2 = 1.1ut + 1/2 ft*t
The range is dependant on t. the longer t is the greater the range and the lesser effect the increase in speed has on the range. However the change in range s2 -s1 is 10% of the initial velocity times the time of flight.

Answer 3

ok, here's what i did

x= range
v= velocity
t= time

x1=v1/t
x2=v2/t

v2=v1*1.1

1.1is 110%

we suppose that t1=t2, so you solve the equations for t and equal them

v1/x1=v2/x2

since v2=1.1*v1 ten

v1/x1=1.1*v1/x2

v1/v1=1 so

1/x1=1.1/x2

now you solve for x2

x2=1.1*x1

so the increase in percentage ow the range will be 10%

hope this helps.

Answer 4

http://www.martindalecenter.com/Calculators4_2_Mech.html