of the packets that the TCP/IP protocol produces when it breaks down data? If each character is represented by 2 bytes, how many packets are needed to transfer the message, our group meeting is next week?
2006-06-25 08:54:41 · 2 answers · asked by Dilmer Valecillos 1 in Computers & Internet ➔ Computer Networking
Sounds like you're fishing for easy answers to home work questions... Anyway, it might be a trick question. TCP has options in the header that allow it to specify the MSS, maximum segment size, so it can have different values. In addition, every network path has an MTU, maximum transmission unit. The ideal case is when one TCP segment fits into one IP packet which then fits into one Ethernet frame. The 802.3 frame format allows up to 1500 bytes in the data section. Take out 20 bytes for the IP header and 20 bytes for the TCP header, and you've got 1460 bytes of character data. So your message "our group meeting is next week" will easily fit into one TCP segment and then one IP packet and then one Ethernet frame. This is if you have TCP/IP/Ethernet. If you have some other underlying medium, like ATM, then you have to divide this up into 53 byte cells, 48 of which are data. So then you would have 3 characters per packet/cell. Then you message "our group meeting is next week" including spaces is our _gr oup _me eti ng_ is_ nex t_w eek which seems to be 10 packets/cells.
2006-06-25 09:17:51 · answer #1 · answered by networkmaster 5 · 0⤊ 0⤋
An Asynchronous Transfer Mode network packages data into standard size blocks (53 bytes: 48 for the data and 5 for the header).
2006-06-25 16:05:30 · answer #2 · answered by mikeagonistes 2 · 0⤊ 0⤋