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9 answers

you can just take the test if you are working, in a pharmacy for example.....that's what I did. I was working at Walgreens..and they paid for the test. I didn't take any classes...but they gave me some information to review...

FYI: it's not a high paying job if you are considering this as a career....retail you'll probably make about $10/hr certified..and in a hospital...maybe 12-14.

2006-06-25 05:50:33 · answer #1 · answered by loubean 5 · 0 0

If by x-ray tech, you mean radiological tech- by far a rad tech makes more. An x-ray tech certification usually does not qualify you as a rad tech, but just to do x-rays at a dentist or docs office. You need a 2 year degree for a rad tech. If looking at just certifications, a pharmacy tech would probably make more

2016-03-27 03:53:12 · answer #2 · answered by Anonymous · 0 0

I took a corespondent course, cheaper then college ($1200) and I could do everything on line. So I continued to work full-time and do my studies, some companies do certify their techs but I don't think it's equivalent to schooling...good luck Oh you could always contact CAPT (Canadian association of pharmacy technician), they might be able to direct you in some of your questions

2006-06-25 06:23:05 · answer #3 · answered by ME 2 · 0 0

educational requirement AND test

2006-06-25 05:43:19 · answer #4 · answered by shehawke 5 · 0 0

no you can't just take a test. Schooling is required

2006-06-25 05:42:14 · answer #5 · answered by nastaany1 7 · 0 0

I believe its like a one year class and then you're able to take the test.

2006-06-25 06:05:15 · answer #6 · answered by Kylah 2 · 0 0

You do have to go to school. Look into a school in your area if thats what you are interested in.

2006-06-25 05:45:06 · answer #7 · answered by winona e 5 · 0 0

none you jsut take the course, i did it in 4 months by correspondence.
www.educationdirect.com

2006-06-25 05:42:43 · answer #8 · answered by Anonymous · 0 0

need 2 b certified i would think

2006-06-25 05:42:46 · answer #9 · answered by Anonymous · 0 0

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