Also the shot angle is at 25 Degrees and from and distance of 6.02 M. What is the release speed of the ball to make the basket?
2006-06-25 05:20:47 · 2 answers · asked by jamey.moore@sbcglobal.net 1 in Science & Mathematics ➔ Physics
The height of the trajectory is 1 m (3.05-2.05)
The horizontal distance is 6.02 m
Now you have ucos(25)t = 6.02
and usin(25)t-0.5*9.8*t^2 = 1
Substitute t = 6.02/ucos(25) in the 2nd eqn and solv.
2006-06-25 05:28:52 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 1⤋
Does it somehow help your ego to get your homework answered by someone else or do you consider it cheating?
At least the first person had the sense to not give you the answer.
If you really are determined not to know the correct answer, just stay asleep in maths class and pay it the same attention you would to an advert for haemorrhoid cream.
If you really understood the question and the science involved, you'd realise that the answer is indeterminate as there is more than one way to make the shot from your initial info and there are in reality an infinite number of solutions. I'll let you consider why..
2006-06-25 06:16:32 · answer #2 · answered by Anonymous · 0⤊ 0⤋