Adult tickets for a play cost $9 and child tickets cost $8. If there were 23 people at a performance and the theater collected $193 from ticket sales, how many children attended the
2006-06-25 03:47:57 · 8 answers · asked by spontanious402000 1 in Science & Mathematics ➔ Mathematics
8x+9(23-x)=193
207-x=193
x=14
nmbr of children = 14
2006-06-25 03:50:36 · answer #1 · answered by Anonymous · 0⤊ 1⤋
14 children
9 adults
#1: 8x + 9y = 193
#2: x + y = 23 > x = 23 - y
plug #2 into #1 for x
8(23 - y) + 9y = 193
184 - 8y + 9y = 193 > 184 + y = 193
y = 9
plug into #2
x + 9 = 23
y = 14
x is children
y is adults
2006-06-25 10:50:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Adult Ticket = $9
Child Ticket = $8
Total people = 23
Total Money collected = 193
Cildren attendence = ? = x
Adults attendence = ? = y
x+y=23 equation # 1
8x-9y=193 equation # 2
multiply 8 with eq #1 to equalize both eqs for subtraction
8(x+y=23)
8x+8y=184 equation # 3
Subtract equation # 2 & 3
8x-9y=193
8x+8y=184
- - -
__________
0 -17y=9
y=9+17
y=26
now put the value of y in eq # 1
x+y=193
x+26=23
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2006-06-25 11:26:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Let a be the number of the adult
and
Let c be the number of the children.
9a+8c=193
a+c=23
Try to find c from these equations
Multiply the second equation by -9
9a+8c=193
-9a-9c=-207
Find the sum side by side
0-c=- 14
Multiply by minus sign
You will get the answer as c=14
2006-06-25 10:55:50 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
9 adults 14 children
2006-06-25 10:54:50 · answer #5 · answered by Anonymous · 0⤊ 0⤋
14 children and 9 adults attended the concert
2006-06-25 10:52:32 · answer #6 · answered by Niebla 2 · 0⤊ 0⤋
9x + 8y = 193
x + y = 23
x + y = 23
y = -x + 23
9x + 8(-x + 23) = 193
9x - 8x + 184 = 193
x + 184 = 193
x = 9
y = -x + 23
y = -9 + 23
y = 14
9 adults
14 children
ANS : 14
2006-06-25 12:56:22 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋
Spelling question - Algebra?
2006-06-25 10:51:33 · answer #8 · answered by 2007_Shelby_GT500 7 · 0⤊ 0⤋