horizontal asymptote: y = 3
horizontal asymptote: y = - 3
horizontal asymptote: x = 3
horizontal asymptote: y = 5
2006-06-24 22:00:24 · 6 answers · asked by Anonymous in Education & Reference ➔ Higher Education (University +)
Dbalze. If you don't have any positive input keep your comments to yourself. Users looking for help don't need your not so clever comments. I find your comment juvenile and unnecessary. The intelligent action would've been to ignore the question if you didn't want to answer. Instead, you chose to answer. Hmph.
Thank you other great thinkers for your willingness to help.
2006-06-25 06:52:16 · update #1
The vertical asymptote is the equation x=6.
The horizontal asymptote is R'(x). Therefore, the horizontal asymptote is the equation y=3.
This function does not have oblique asymptotes.
2006-06-24 22:16:14 · answer #1 · answered by G. Rex 3 · 0⤊ 0⤋
Verticalal asymptote: x= 6, since x cannot equal 6. This would be dividing by zero
Horizontal one is y=3. I don't know what an oblique one is.
2006-06-25 06:19:47 · answer #2 · answered by demaman 3 · 0⤊ 0⤋
I know the vertical is x = 6, because you have to set the bottom equal to zero so that you can find the undefined points in the function. I don't feel like thinking about the rest :P
2006-06-25 05:07:59 · answer #3 · answered by Pawl M Davis 3 · 0⤊ 0⤋
-2
2006-06-25 05:04:31 · answer #4 · answered by David L 2 · 0⤊ 0⤋
vertical: x = 6
not sure about the rest
2006-06-25 05:05:35 · answer #5 · answered by peace_n_luv 3 · 0⤊ 0⤋
Hmmm.... Looks like the answer is:
D(o) - (y+o(ur) ow/n dam-n)
-------------------------------------------------------------
(h+om) + (ew(ork))!
2006-06-25 05:04:31 · answer #6 · answered by Anonymous · 0⤊ 0⤋