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2006-06-24 21:41:24 · 3 answers · asked by jcv.lagniappe 1 in Education & Reference Higher Education (University +)

Thanks guys. I love see things worled out!!

2006-06-25 06:19:01 · update #1

3 answers

No maximum (because as x outside of -1 to 1 increases, y increases rapidly)
The minimum is -1, at x=0.5.
For the moment, drop the factor 4.
Consider x^2 - x
Is x^2 greater than x? Yes, for all x > 1, and x<-1 it is. But its not for |x| in 0 to 1. The difference is highest when x = 0.5, therefore f(x) is least at x = 0.5

2006-06-24 21:53:49 · answer #1 · answered by vin 3 · 1 0

minimum: if x=1/2, y =-1

2006-06-25 04:48:52 · answer #2 · answered by Anonymous · 0 0

No, it does not.

2006-06-25 04:45:39 · answer #3 · answered by cyanne2ak 7 · 0 0

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