2006-06-24 17:44:25 · 13 answers · asked by bobbyhope83 1 in Games & Recreation ➔ Video & Online Games
This is about two items in World of Warcraft, that many players have asked. One is a weapon, the other is a shield.
2006-06-24 17:52:50 · update #1
Unstoppable Force will succeed since even if the Immovable Object blocks, the amount of blocking power that it has much less than the damage the Unstoppable Force can do. So damage would always get through.
Unstoppable Force: 175-292 damage
Immovable Object: 71 blocking
2006-06-24 22:27:24 · answer #1 · answered by J L 2 · 0⤊ 0⤋
I would suggest that the unstopable force would move through the immoveable object like wind through a screen. Both would be equally successful.
2006-06-25 00:49:52 · answer #2 · answered by kev 3 · 0⤊ 0⤋
well if the force is really unstoppable and the object truly is immovable, neither of them will succeed.
2006-06-25 00:48:14 · answer #3 · answered by Well i Say.. 3 · 0⤊ 0⤋
The properties of "unstoppable" and "immovable" would be determined only after such a sequence.
2006-06-25 00:49:13 · answer #4 · answered by perfectlybaked 7 · 0⤊ 0⤋
I think the unstopable force because the force is unstoppable and i don't think something can never be moved.
2006-06-25 00:52:37 · answer #5 · answered by Nicholais S 6 · 0⤊ 0⤋
You're playing word games. That's not a real problem. That's like saying "what if 2 were 3". it just doesn't make sense.
2006-06-25 00:48:48 · answer #6 · answered by bigjarom 4 · 0⤊ 0⤋
the unstoppable force
2006-06-25 00:51:31 · answer #7 · answered by midnight red 2 · 0⤊ 0⤋
depending on their masses and the velocity of that travelling force.
2006-06-25 02:36:46 · answer #8 · answered by lilser 1 · 0⤊ 0⤋
that's like asking if god could warm a burrito so hot that he himself couldn't eat it. the world will never no.
2006-06-25 00:48:18 · answer #9 · answered by The Riddler 3 · 0⤊ 0⤋
as with all things in the realm of problem solving, it all depends on one's frame of reference.
2006-06-25 00:58:53 · answer #10 · answered by ainep 1 · 0⤊ 0⤋