how do you factor this?

Question

3a2(that's squard)+6ab+3b2(squard)+7a+7b-6

3a^2+6ab+3b^2+7a+7b-
6

Once again just to clarify the problem is:
3a^2+6ab+3b^2+7a+7b-6

Answer 1

First look at the highest powers of a and b which in this case is "squared" and the product 6ab is present, so factoring will likely involve (a+b)^2
In fact 3a^2+6ab+3b^2 = 3(a^2+2ab+b^2) = 3(a+b)^2
So your problem reduces to:

3(a+b)^2 +7(a+b) - 6

If we choose to factor -6 as -2 x 3 then the it is easy to factor, and the solution is:

(3(a+b) -2)((a+b)+3)

Answer 2

since i can't see the entire problem

3a^2 + 6ab + 3b^2 + 7a + 7b - ....

Go to www.quickmath.com, click on Factor under Algebra, and this will factor it for you.

Answer 3

The best i can do is:

(3a + 3b)(a + b) + 7(a + b)

Answer 4

(a+b+3)*(3a+3b-2)

:)