Other than (122+121)*(122-121)
2006-06-24 15:30:44 · 7 answers · asked by Andrea 3 in Science & Mathematics ➔ Mathematics
122*122-121*121=(121+1)(121+1) -121*121 =
121*121+121+121+1-121*121=
121+121+1=
243
:)
2006-06-24 20:13:56 · answer #1 · answered by Theta40 7 · 2⤊ 0⤋
The difference between consecutive squares equals the sum of the square roots. To express numerically:
122*122 - 121*121 = 122 + 121 = 243
2006-06-25 01:16:35 · answer #2 · answered by jimbob 6 · 0⤊ 0⤋
122*122-121*121 =
122^2 - 121^2 =
243 or 3^5
122*122 - 121 * 121
2006-06-24 22:37:19 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
The correct methood of doing this is (122*122)-(121*121)=14884-14641
=243
2006-06-24 22:37:35 · answer #4 · answered by Ganch222222213 2 · 0⤊ 0⤋
(x+1)^2 - x^2 where x is 121
= 2x + 1 = 243
Someone have a calculator? Geez, I used to be real smart.
Seriously, we used to have to solve these things rather than just calculate. With fast computers and cheap calculators, it's become a lost art. That and walking five miles uphill to school. And back.
2006-06-24 22:34:25 · answer #5 · answered by Bill S 6 · 0⤊ 0⤋
This problem has been done in many ways.The one u have said is the simplest.The basic method is to square the nos. and then substract them.
Considering the eqn as (x+1)^2 -x^2 is just another way of writting x^2=(x+1)^2-(x-1)^2.(The variables are defined differently)
Like this, u can also write it as x^2-(x-1)^2
2006-06-25 01:50:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋
yes
2006-06-24 22:34:46 · answer #7 · answered by b-ballchick94 1 · 0⤊ 0⤋