2006-06-24 12:28:37 · 9 answers · asked by Ann M 1 in Science & Mathematics ➔ Physics
125 mph it's the same for all things dropped
2006-06-24 12:33:10 · answer #1 · answered by Iron Rider 6 · 2⤊ 1⤋
well, using the formula for terminal velocity of, V = sqrt ( (2 * W) / (Cd * r * A). and plugging in the necessary parts, you get 3.96144 feet per second for an empty porta-potty, and 12.5294400 feet per second for a filled porta-potty
2006-06-24 19:59:53 · answer #2 · answered by double0agent2002 2 · 0⤊ 0⤋
the terminal velocity of a skydiver in a normal free-fall position with a closed parachute is about 120 Mph. It would take about 5.5 seconds to reach that speed. This speed increases to about 200 Mph if the skydiver pulls in his limbs. But their are just to many veriables with a Port-O-John.
2006-06-24 19:34:11 · answer #3 · answered by wolfmano 7 · 0⤊ 0⤋
That depends on how much the porta potty weights!
2006-06-24 19:34:21 · answer #4 · answered by arunhn 3 · 0⤊ 0⤋
Assuming the door doesn't flap open or fly off; I heard years ago that th terminal velocity of a brick-shaped object (rectangular all over) is about 120 mph.
2006-06-24 19:35:32 · answer #5 · answered by fata minerva 3 · 0⤊ 0⤋
Haha. Don't really know the answer to that one. Why on earth do you need to know that? Nevermind. I really don't want to know. Just post the video on the internet so we can all get a good laugh.
2006-06-24 19:31:54 · answer #6 · answered by goodtimesgoodtymes 2 · 0⤊ 0⤋
Depends on the distance fallen among other things.
2006-06-25 00:24:48 · answer #7 · answered by butch 5 · 0⤊ 0⤋
Is there a person inside? Is it full or empty?
2006-06-24 19:33:10 · answer #8 · answered by mightymite1957 7 · 0⤊ 0⤋
What a shite question!
2006-06-24 19:31:48 · answer #9 · answered by Anonymous · 0⤊ 0⤋