Some scientists want to create a new kind of liquid. One liquid contains 8% sodium (Na) and the other liquid contains 15% sodium (Na). Once they mix the two liquids the resulting chemical contains 11% sodium (Na). How many milliliters (ml) of each liquid must be mixed to obtain 300 ml of the new liquid?
2006-06-24 11:08:19 · 5 answers · asked by ladiejay71 1 in Science & Mathematics ➔ Mathematics
Let x be liquid A.
& y be liquid B.
Then,
x + y = 300 First Equation
0.08x + 0.15y = 0.11 (300) Second Equation
Solving the simultaneous equation, we get
x = 171.43 ml
y = 128.57 ml
2006-06-24 11:28:19 · answer #1 · answered by Xtreem 2 · 1⤊ 1⤋
Easy. The one liquid is "3" away of the new mix goal (11-8), the other one is "4" away (15-11). So the relation of the two liquids must be 3:4 the other way round.
300ml/7*3 of the 15-mix
300ml/7*4 of the 8-mix
All clear?
2006-06-24 18:16:24 · answer #2 · answered by swissnick 7 · 0⤊ 0⤋
Let x = # of ml of 8%
(300 - x) = # of ml of 15%.
8%(x) + 15%(300 - x) = 11%(300)
Solve for x.
2006-06-24 18:15:27 · answer #3 · answered by Big D's Tuna 2 · 0⤊ 0⤋
1:9
2006-06-24 18:15:45 · answer #4 · answered by precede2005 5 · 0⤊ 0⤋
I would do something like the following;
8x + 15x = 11x
solve and find the value of x.
well, i'm not sure it's like this, but this may give you an idea.
2006-06-24 18:20:09 · answer #5 · answered by Rocio 2 · 0⤊ 0⤋