Algebra Help 2?

Question

2x+3y=14
x +2y=18

Answer 1

Take eq2 and slove for x
x+2y=18
x=18-2y eq3

substitute x in eq.2 the result of eq3
2x+3y=14
2(18-2y)+3y=14
36-4y+3y=14
-y=14-36
-y=-22
y=22

now subsitute the value of y to eq2
x+2y=18
x+2*22=18
x=18-44
x=-26

Hence x=-26 and y=22

Answer 2

This is a system of equations, two variables to solve for.

Substitution Method:
2x + 3y = 14
x + 2y = 18

x = 18 - 2y
Substitute 18 -2y for x in the first equation
Instead of 2x + 3y = 14, write: 2(18 - 2y) + 3y = 14
Then: 36 -4y +3y = 14
36 - y = 14
22 = y
Now, substitute 22 for y in the first equation:
2x + 3*22 = 14
2x + 66 = 14
2x = -52

x = -26
y = 22

Elimination Method:
Multiply the second equation by 2(its still the same equation!):

2x + 3y = 14
2*x + 2*2y = 2*18

Now, subtract the entire second equation from the entire first:

2x + 3y = 14
-2x - 4y = -36

0 - y = -22
y = 22
As in the first method, substitute 22 for y in the first equation:
2x + 3*22 = 14
2x + 66 = 14
2x = -52

x = -26
y= 22

Answer 3

2x+3y=14
x+2y=18 (-2)

-y=-22
y=22
2x+66=14
x=-26

2 (-26) + 3 (22) = 14

x = -26 y = 22

Answer 4

Simultaneous equations. Rearrange one so that it is in terms of x or y, then substitute that for x or y into the other one.

Do your own damn homework.

Answer 5

2x+3y=14
-2x-4y=-36

y=22

2x=14-66====>x=52/2
x=-26

Answer 6

2x+3y=14-------eq.1
x+2y=18---------eq.2

multiplying eq.2 with 2

2x+3y=14
2x+4y=36
- -- -
-------------
7y= 50

y=50/7

lly, find the second one LOL

Answer 7

Its possible. Its linear equations..but I dun feel like doing it

Answer 8

x= -26
y = 22

Answer 9

Will i get a noble prize for maths this year if i answer this ??

:P:P

Answer 10

do ur hw urself