1 - A is enough because with the lengths of 2 sides you can use pythagoras' theorem to work out the length of the other
2006-06-24 02:49:46
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answer #1
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answered by Ivanhoe Fats 6
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1 and 2 are correct.
1. A is enough because then, with one side being 5 cm, and the other being 6, then the third side must equal sqrt(6^2 - 5^2), or sqrt(11).
2. B is enough because if one angle is 45 degrees, the other acute angle must also be 45 degrees, and therefore, the three sides are 5 cm, 5 cm, and sqrt(50) cm.
Note that these two statements give two different solutions, and therefore cannot be together. So 3 & 4 are not correct.
2006-06-24 03:00:42
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answer #2
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answered by Anonymous
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1- A is enough (TRUE)
You use Pythagoras to find the 3rd side.
SQRT(6^2-5^2)=SQRT(11)=~ 3.31
2- B is enough (TRUE)
If one angle is 45 degree, the other MUST be 45 too.
Because this, both sides HAS to be equal (5 cm each).
Therefore, hypotenuse = SQRT(5^2+5^2) = SQRT(50)=~ 7.07
3 - A&B are required (FALSE)
Hyputenuse is 6 cm as stands "A" OR 7,07 cm as stands B
Options are incompatible, cant be true toghether.
4 - A&B are not sufficient (FALSE)
A OR B are enought.
2006-06-24 03:15:07
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answer #3
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answered by i g 3
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Since it is a right angled triangle with one of its angle 45 degree, implies that the legs are equal as the remaining angle should also be 45 degree. Hence hypotenuse of such triangle is also equal to the diagonal of the square of its leg. And if `a' is the side of such a square we have, 2a^2=6^2
ie. a^2=(6^2)/2
Then, a (or legs of the right triangle)=6/sqrt2
Opinion- A&B are required.
2006-06-25 02:22:00
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answer #4
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answered by shasti 3
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ANS : 1.) A is Enough
a^2 + b^2 = c^2
a^2 + 5^2 = 6^2
a^2 + 25 = 36
a^2 = 11
a = sqrt(11)
2006-06-24 02:56:37
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answer #5
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answered by Sherman81 6
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A is enough, becasue u already have 2 sides given. i think the angle was given to through you off. LOL
and u can use pythagoras....i got 3.316 624 79
2006-06-24 02:58:33
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answer #6
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answered by bahamiano 3
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1 A is enough
you've got 2 sides already and you know its a right triangle..
2006-06-24 03:00:51
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answer #7
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answered by ThaNix 2
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1 and 2 are correct. With A, you can use pythagoras
with B, you can use tan=opp/adj
2006-06-24 02:53:30
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answer #8
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answered by anon1mous 3
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3 A&B are required
2006-06-24 02:53:24
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answer #9
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answered by Anonymous
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(2)-3.31
2006-06-24 02:52:25
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answer #10
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answered by Michelle D 2
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