1/a+b+x=1/a+1/b+1/x?

Answer 1

1/a+b+x= 1/ (a+b+x)= (1/a) + (1/b) +(1/x)

So, it basically saying 1 over a+b+x, therefore (1/a)+(1/b)+(1/x) is the same because its taking 1 and then individually dividing it with each component such as a or b or x. So if you did this numerically, then it would be something like 1/2+3+4 would equal the same as adding (1/2) + (1/3)+(1/4)....if you don't believe you can check the numerical values with a calculator.

Answer 2

1/a+b+x=1/a+1/b+1/x

b+x = 1/b + 1/x

b+x = (x+b)/bx

bx = 1

Thus, many answers for b and x.

Answer 3

There doesn't appear to be a single answer to this. Simplified I get:

x^2 + b^2 - 2 = 0

There could be multiple answers for x and b.

Answer 4

1/a+b+x=1/a+1/b+1/x
=>1/a+b+x-1/a=1/b+1/x
=>a-a-b-x/a(a+b+x)=b+x/bx
................................................................
solve it by urself
the answers are x=-a or x=-b

Answer 5

ewww, math.

Answer 6

its difficult