2006-06-23 22:04:20 · 18 answers · asked by rma 1 in Science & Mathematics ➔ Mathematics
2^1999 x 5^2000 =
2^1999 x 5^1999 x 5 =
(2 x 5)^1999 x 5 =
5 x 10^1999
This is 5 followed by 1999 zeroes.
This an exact aresult.
2006-06-23 22:21:11 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
2^1999+5^2000
=5.e+1999
2006-06-23 23:48:20 · answer #2 · answered by jason2peters 1 · 0⤊ 0⤋
5*10^1999
2006-06-24 01:56:49 · answer #3 · answered by lex_szoke 2 · 0⤊ 0⤋
ANSWER A
2 to the power of 1999 = 5.740653476371272621164166005888e+601
ANSWER B
5 to the power of 2000 =
8.70980981621721667557619549478e+1397
answer a X answer b = 5.e+1999
2006-06-23 22:13:01 · answer #4 · answered by Anonymous · 0⤊ 0⤋
5^1999
2006-06-24 03:23:09 · answer #5 · answered by Chris 1 · 0⤊ 0⤋
2 to the power of 1999 = 3996001
5 to the power of 2000 = 32000000000000000
multiplting both this nos. gives:
12787203200000000000000000
2006-06-30 15:08:18 · answer #6 · answered by hemang8 1 · 0⤊ 0⤋
ya chemboy is correct.good job.
just combine 1999 twos with 1999 fives to get 10^1999
so the answer is 5*(10^1999)
2006-06-23 22:25:16 · answer #7 · answered by Phdinlove 1 · 0⤊ 0⤋
5^9 x 5^9 = 5^18 because of the fact the exponents (9) are further whilst enhanced to numbers of the comparable base (5). 5^9 / 5^9 = a million because of the fact any variety divided by potential of itself equals a million. as an occasion, 3/3 = a million.
2016-12-13 18:31:48 · answer #8 · answered by immich 4 · 0⤊ 0⤋
5 *10^(1999)
i.e 5 followed by 1999 zeroes
huh...
2006-06-23 22:12:55 · answer #9 · answered by Anonymous · 0⤊ 0⤋
going to be more than the 2 points i just got
2006-06-23 22:11:00 · answer #10 · answered by Anonymous · 0⤊ 0⤋