linear equation
2006-06-23 20:49:45 · 6 answers · asked by arijit m 1 in Computers & Internet ➔ Other - Computers
you havn't specified what you want solved?
2006-06-23 20:53:50 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3x + 4y = 12
(m+n)x + 2(m-n)y = 5m - 1
m + n = 3
m = 3 - n
2(m - n) = 4
2((3 - n) - n) = 4
3 - 2n = 2
-2n = 2 - 3 = -1
2n = 1
n = 1/2
m = 3 - 1/2
m = 5/2
...I think that's right.
2006-06-24 04:00:53 · answer #2 · answered by Kelsey 2 · 0⤊ 0⤋
Nuh uh. No way am I going to solve that at 3 am. Try asking around noon tomorrow after I wake up! Im going to sleep now. Nighties whoever you are!
SHUT UP I KNOW I'M WEIRD!
2006-06-24 03:52:47 · answer #3 · answered by Anonymous · 0⤊ 0⤋
assume m=2 and n=1 put value of m and n ...equ. will be 3x+2y=9.....................(2) , 3x+4y=12..............(1) subtract equ. (1) and(2) ..result will be y=3\2 ..put value of y in any of the equ..x=2 hence ans of the question is y=3\2 ,x=2
2006-06-24 04:07:20 · answer #4 · answered by Atul 1 · 0⤊ 0⤋
The comma in there is throwing me off.
2006-06-24 03:53:15 · answer #5 · answered by K4P741N_KRUNCH 2 · 0⤊ 0⤋
I think I am, there for I am
2006-06-24 04:09:34 · answer #6 · answered by Paul G 5 · 0⤊ 0⤋