In the equation 1/x=1/a+1/b.....
how can i transform it so i can solve it in terms of a ...i can only use the variables.....
2006-06-23 16:28:36 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
1/x = 1/a + 1/b
1/x - 1/b = 1/a
b/bx - x/bx = 1/a
(b-x)/bx = 1/a
a(b-x)/bx = 1
a = bx/(b-x)
2006-06-23 16:34:22 · answer #1 · answered by theFo0t 3 · 0⤊ 0⤋
x to the -1 exponent = a to the -1 + b to the - 1, because 1/x = 1 to the -1 exponent.
So x to the -1 minus b to the -1 = a to the negative 1.
So... a = bx/(x-b)
( The foot submitted his answer before mine, they're the same, but I prefer negative exponents to fractions.)
2006-06-23 23:36:08 · answer #2 · answered by Ryan rox 3 · 0⤊ 0⤋
a=b over x+2
2006-06-23 23:33:37 · answer #3 · answered by Steve E 2 · 0⤊ 0⤋
Put some spaces into your equation as we can't see anything past 1/b.
2006-06-23 23:40:52 · answer #4 · answered by Mike B 3 · 0⤊ 0⤋
1/x = 1/a + 1/b
1/a = 1/b - 1/x
1/a = (x-b)/(bx) //cross multiply
a = bx/(x-b) //take reciprocal
That's it. Easy, huh?
2006-06-23 23:34:41 · answer #5 · answered by anonymous 7 · 0⤊ 0⤋
First multiply by a b and x they will no longer be denominators
Go from there
2006-06-23 23:33:49 · answer #6 · answered by suttlegn123 2 · 0⤊ 0⤋
1/a = 1/b - 1/x
1/a = (x-b)/bx
a = bx/(x-b) Maybe? I tried
2006-06-23 23:41:40 · answer #7 · answered by Tony 3 · 0⤊ 0⤋