an irriesponsible student tore his assiment sheet in half. then tore each of the remaining peices in half. he continued this process 7 more times how many peices of paper did he have at the end?
2006-06-23 16:08:45 · 14 answers · asked by koalabear 2 in Science & Mathematics ➔ Mathematics
256
2006-06-23 16:11:33 · answer #1 · answered by Anonymous · 0⤊ 0⤋
the equation than formed is = n =2 to the power n
where n is the no of times he tore the sheet.
as he tore 9 times
therefore ans is 512
2006-06-23 23:14:45 · answer #2 · answered by aashg 2 · 0⤊ 0⤋
He tore them in half once. Then he did it again, and then another seven times, for a total of nine. Therefore, the number of pieces is 2^9, which is 512.
2006-06-23 23:12:14 · answer #3 · answered by Pascal 7 · 0⤊ 0⤋
The answer is 256!
The equation doesn't start until after the first tear when you have two pieces of paper. Then it doubles eight times there after.
So the equation is: 2 raised to a power of 8 = 256!
2006-06-23 23:37:23 · answer #4 · answered by M4free 1 · 0⤊ 0⤋
tore the page once means 2 pieces
second time another 2 pieces
i.e. 2 + 2 = 4
continued it 7 more times
therefore we can say;
2^7
which equals 512
2006-06-24 20:11:22 · answer #5 · answered by bz_co0l@rogers.com 3 · 0⤊ 0⤋
total number of pieces= 2^9 =512
2006-06-24 00:03:22 · answer #6 · answered by abhinav 2 · 0⤊ 0⤋
1st tear --> 2 pieces
2nd tear --> 2*2 = 4 pieces
3rd tear --> 4*2 = 8 pieces
4th tear --> 8*2 = 16 pieces
5th tear --> 16*2 = 32 pieces
6th tear --> 32*2 = 64 pieces
7th tear --> 64*2 = 128 pieces
8th tear --> 128*2 = 256 pieces
2006-06-23 23:24:09 · answer #7 · answered by horensen 4 · 0⤊ 0⤋
162
2006-06-23 23:12:51 · answer #8 · answered by joy g 1 · 0⤊ 0⤋
2^(2 + 7) = 2^9 = 512
ANS : 512
2006-06-24 00:59:10 · answer #9 · answered by Sherman81 6 · 0⤊ 0⤋
512 ?
2006-06-23 23:13:31 · answer #10 · answered by Anonymous · 0⤊ 0⤋