math question 2?

Question

the sum of four consetative odd intergers greater than96 what is the minimum value of the first interger?

the sum of 4 consetative odd intergers is greater than 96 what is the minimum value on the 1st interger

Answer 1

what does "consetative" odd "intergers" mean ?

Answer 2

x + (x + 2) + (x + 4) + (x + 6) > 96
x + x + 2 + x + 4 + x + 6 > 96
4x + 12 > 96
4x > 84
x > 21

so the next odd interger that is greater than 21 is 23

The consecutive odd intergers are 23, 25, 27, and 29

ANS : 23

Answer 3

let the first odd integer be x
therefore other would be x+2, x+4 , x+6

as sum is greater than 96

therefore x+x+2+x+4+x+6> 96

4x + 12> 96
x > 21


therfore first integer should be greater than 21 but not 21 therefore your ans is 23

Answer 4

Let's see . . .
Let n be the first odd integer.
n + (n+2) + (n+4) + (n+6) = 96 = 4n + 12
4n = 96 - 12 = 84
n = 84/4 = 21
So, for their sum to be greater than 96 the first integer must be 23.

Answer 5

n first odd integer
n+n+2+n+4+n+6>96
4n>84
n>21
then the first integer that is minimum is 23 because this will be exceed the value of 96 when you add the next 3 consecutive odd integer with the 21 so there are 4 to be added to be exceed

Answer 6

x+x+2+x+4+x+6>96
4x+12>96
x+3>24
x>21
the minimum value if the first integer is greater than 21

gimme 10 points buddy!

Answer 7

the sum must be greater that 96? your answer is 23

your integers are 23, 25, 27, 29

(for those below)
it must be greater than 21, therefore it canot be 21

Answer 8

the integers would be x, x+2, x+4, and x+6
you add them together and the sum is less than 96
so
4x+12 is less than 96
solve using algebra and x is your answer
also x should be odd if not add 1 to make it odd

Answer 9

are the integers greater than 96, or is their sum greater than 96?

Answer 10

um, i think you forgot some info. If you didn't, then the answer is 97.