how many variations of 4 digits can there be made using numbers 0-9?

Answer 1

10000

That's counting 0000, 0001, 0002, all the way to 9999

Answer 2

hi, The question is relating to permuations and mixtures. you've those 10 numbers: 0, a million, 2, 3, 4, 5, 6, 7, 8, 9 assume you want the numbers to commence with 0, then the fashion of opportunities will be: 10 x 9 x 8 x 7 = 5040 First you've 10 opportunities. After determining on the first huge type, you've in uncomplicated phrases 9 selections, then 8 selections and ultimately 7 selections. Now, in case you do not favor the large type to commence with 0. Then, initially you've 9 selections. Then, you lower back throw the 0 in the list, which brings you to a distinct 9 selections. After determining on the 2d digit, you're left with 8 selections and ultimately 7 selections. 9 x 9 x 8 x 7 = 4536 wish it helped you :-)

Answer 3

First digit should not be 0 because it becomes 3 digit number. so, 9*10*10*10=9000 variations can be formed.

Answer 4

let teh number be represented by _ _ _ _
now the first dash can be filled up in 9 ways ( by the numbers 1-9 . it cannot be filled by 0 since then it would become a 3-digit number)
the 2nd , 3rd, 4th digits can be filled up in 10 ways (by all the digits 0-9)
So the total possible combinations are : 9*10*10*10=9000

Answer 5

well,
if you consider that 0 can be first -
the answer is 10 x 10 x 10 x 10--
but if 0 can't be first, then
9 x 10 x 10 x 10

if a number can only be used once,
then
10 x 9 x 8 x 7

just get a calculator

Answer 6

10numbers 4 digits. so, 10^4=10000

Answer 7

10^4 or 10000

Answer 8

0123 1230 2310 3012 3021 3201 3120 0321 0231 0

1234 1342 1324 1243 1423 1432 2134 2143 2341 2314 2431 2413 3214 3124 3412 3421 3124 3142 3214 3241 4123 4132 4213 4231 4321 4312 5432 5423 5324 5342 5234 5243 6543 6534 6435 653 6345 6354 7654 7645 7546 7564 7456 7465 8765 8756 8675 8657 8567 8576 9876 9867 9786 9768 9678 9687 1234 5678 1368 4567 9587 1524 0687 3640 1020 1030 1040 1050 1060 1070 1080 1090 A LOT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 9

10,000, any four digit number plus 0 makes 10,000 numbers

Answer 10

nPr = (n!)/((n - k)!)

10P4 = (10!)/((10 - 4)!)
10P4 = (10!)/(6!)
10P4 = (10*9*8*7*6*5*4*3*2*1)/(6*5*4*3*2*1)
10P4 = 10 * 9 * 8 * 7
10P4 = 5040

assuming that you can use the same number twice

Answer 11

9000 variations