There is no single value for x or y. Still, we can solve for both.
10x+8y=100 <-lets get rid of the multiplier of x, divide by 10
x+0.8y=10 <-now lets get x alone, subtract 0.8y
x=10-0.8y <-this equation defines x
10x+8y=100 <-lets get a single y, divide by 8
1.25x+y=12.5 <-again, get y alone, subtract 1.25x
y=12.5-1.25x <-this equasion defines y
Since x and y are not single values but instead equasions, this is the best you can do. Plug in whatever values you want for y in order to come up with what x will have to be to fit your original equasion, and vice versa.
2006-06-23 12:51:23
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answer #1
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answered by Fenris 4
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x=2 y=10
2006-06-23 12:51:09
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answer #2
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answered by Redhothumanity 2
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10x+8y=100
10x=100-8y
10/10x=100/10 - 8/10 y
x=10- 8/10 y
then replace the x with that new equation
2006-06-23 12:57:16
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answer #3
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answered by Stratomanssy 5
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x = 2, y = 10
x = 6, y = 5
2006-06-23 12:51:24
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answer #4
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answered by macvanteh 3
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you have to find x and y
If x = 4 wt is y .. you have to find that and you have to graph it
if x=1
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10x+8y = 100
= 10*4 + 8y = 100
= 40 + 8y = 100
= 8y = 100 - 40
= 8y = 60
= y = 7.5
now see if x=1
y = 7.5
now you write it like this (1,7.5)
its called ordered pairs
you have to fined more .. like if x=2 , x=3 , x=4 , x=5
now you have to graph it ( x comes first and then y)
2006-06-23 13:46:42
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answer #5
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answered by ♥♫♥ÇHÅTHÜ®ÏKÃ♥♫♥ 5
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The only thing you can do with that equation is write it in standard linear form:
8y = 100 - 10x
y = (100/8) - (10/8)x
2006-06-23 15:16:45
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answer #6
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answered by Anonymous
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X=6
Y=5
2006-06-23 14:36:55
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answer #7
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answered by Kee78 1
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As it stands, with no additional information about either x or y, there are multiple answers. For example, x=10 and y=0, or x=6 and y=5.
2006-06-23 12:53:11
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answer #8
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answered by Farly the Seer 5
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Hi my name is Bob,
Your answer I beleive is 9 2/10 or 9 1/5
see ya
2006-06-23 14:46:11
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answer #9
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answered by quinny 1
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x=1; y=82
2006-06-23 12:51:10
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answer #10
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answered by james M 1
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