2006-06-23 10:26:52 · 12 answers · asked by tq 3 in Science & Mathematics ➔ Mathematics
As you can tell from the various answers, your question is ambiguous. If y is a function of x, then d(y^3)/dx = 3y²(dy/dx), using the chain rule, not + dy/dx as metaraison would have it. If y is not a function of x, then dy/dx = 0 as if y were a constant.
2006-06-23 10:53:20 · answer #1 · answered by Philo 7 · 0⤊ 3⤋
I think if it's in respect to x you have to make it X^(1/3) by taking the cube root of y. Then you will take the derivative so it = (1/3)X ^ (-2/3)
2006-06-23 13:36:28 · answer #2 · answered by DaniLynn 3 · 0⤊ 0⤋
d/dx(y^3) ?
That's zero, that function does not have an x component. You really should read up on partial derivatives, it's a critically important subject.
2006-06-23 10:30:09 · answer #3 · answered by Argon 3 · 0⤊ 0⤋
d/dx (y³) = 3y² * (dy/dx)
This is called implicit differentiation, first you differentiate it with respect to y, then you multiply it by (dy/dx).
2006-06-23 10:38:14 · answer #4 · answered by canzoni 3 · 0⤊ 0⤋
i am going to assume you propose: f(x) = y = (sqrt(x))(3x-a million) and also you pick to locate the derivative. if so, then dy/dx = (x^.5)(3) +(3x-a million)(.5)(x^-.5) dy/dx = 3x^.5 +a million.5x^.5 - .5x^-.5 = 4.5x^.5 -.5x^-.5
2016-11-15 04:29:07 · answer #5 · answered by ? 4 · 0⤊ 0⤋
Phil here has the correct answer!
2006-06-23 11:34:32 · answer #6 · answered by akiras mommy 2 · 0⤊ 0⤋
ignore other answers above, you question is flawed. is y a function of x, is y independent of x or not.
2006-06-23 10:32:44 · answer #7 · answered by ghakh 3 · 0⤊ 0⤋
d/dx(y^3) := 3*y^2 + dy/dx
2006-06-23 10:30:11 · answer #8 · answered by metaraison 4 · 0⤊ 0⤋
3ysquare
mind the square is on y
2006-06-23 10:31:00 · answer #9 · answered by ARYAN MANDY 4 · 0⤊ 0⤋
3x^2
2006-06-23 10:29:27 · answer #10 · answered by Anonymous · 0⤊ 0⤋