2006-06-23 10:06:48 · 6 answers · asked by Jeffrey M 1 in Science & Mathematics ➔ Mathematics
That depends on the dimensions of the volume of 115 cubic feet..
If the any of one of the sides is 2 inches, it would fit zero footballs.
If it is a cube with 115 cubic feet,
which is equal to 198 720 cubic inches,
you would get a length of about 58.355 inches for one side,
Across the length it can fit 58.355/3 = 19 footballs
Likewise for the width.
FOr the height, it fits 58.355/6 = 9.725 , i.e. 9 footballs.
Thus the answer would be 19*19*9 = 3249 footballs.
P.S. I'm assuming that 6 inches is the height of the football, but in the case of a cube it doesn't really matter anyway.
2006-06-23 10:29:30 · answer #1 · answered by canzoni 3 · 0⤊ 0⤋
That depends on the dimensions of the 115 cubic feet and on how the footballs are arranged. I'm not sure this problem has even been solved for spheres. If it has, it was recent.
2006-06-23 11:05:28 · answer #2 · answered by Philo 7 · 0⤊ 0⤋
(3/12) = (1/4)
(6/12) = (1/2)
115/((1/4)(1/2)(1/2))
115/(1/16)
(115/1)/(1/16)
(115/1)*(16/1)
1840
ANS : 1840 footballs, assuming that the height and width is 3 inches
2006-06-23 15:16:56 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
Is this football going flat? Everyone knows footballs are round. It sounds more like a junior rugby ball for young children to me.
2006-06-23 10:19:13 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Four.
2006-06-23 10:09:39 · answer #5 · answered by Billy 3 · 0⤊ 0⤋
All of them.
2006-06-23 10:13:02 · answer #6 · answered by Anonymous · 0⤊ 0⤋