You cannot rewrite like this: F(x)=x^-1 becaus the integral of x^a =
x^(a+1)/(a+1) if a is different of -1.
Integral of (1/x) is Ln (|x|) like other people said.
But why?
When the matematicians studied the proprieties of this integral, they discovered that this integral had the same proprieties of the ordinary Log(x).
2006-06-23 09:21:23
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answer #1
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answered by Anonymous
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The antiderivative of 1/x is ln|x| + C
This is just one of those things that you need to memorize. There is actually a way to prove that the integral has the logarythmic property (that ln(a*b) = ln(a)+ln(b)) using u-substitutions. But trust me -- it is better to just memorize it.
2006-06-23 16:52:07
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answer #2
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answered by Ranto 7
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the integration of 1/x is ln|x| + C, where C is a constant.
you can verify it by differentiating ln|x| + C
2006-06-23 17:34:49
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answer #3
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answered by canzoni 3
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The answer is log to the base e x. e = exponential. Can also be written as Inx
2006-06-23 16:06:16
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answer #4
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answered by Numptyhead 2
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Rewrite it as x^-1 and do it the way your teacher taught you the first week of class.
2006-06-23 16:02:32
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answer #5
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answered by Rocket Scientist X 2
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It is usually in the inside cover of your book. that is a typical one that you will have to have memorized.
2006-06-23 16:16:30
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answer #6
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answered by ferronferron 2
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the answer is ln(absolute value of(x ))
this is just a calc property
2006-06-23 16:12:05
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answer #7
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answered by dhaval70 2
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i hate math..
2006-06-23 16:03:20
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answer #8
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answered by Anonymous
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