undefined
2006-06-23 03:03:57
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answer #1
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answered by salvia8791 1
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Any number divided by zero is UNDEFINED. A function that in a value gives the form zero divided by zero is undefined, but the limit of f(x) tending to that value may still be calculated.
When a function tending to a number "a" gives the form 0/0 is probably because the numerator as well as the denominator have a common factor [of the form (x-a)] that when canceled the limit may be calculated.
Take for example:
f(x) = [(x -1) (x +1)] / (x -1)
There you can clearly see that when x = 1 tha function is undefined. Well it turns out that although x = 1 is a prohibited value; to the left and to the right of 1 thev function tends to same number which is 2.
In other words:
LIM F(x) = 2
x ->1
How is this? Well the function given though it is a quotient of polynomials, the entire function behaves as a linear function of the form f(x) = x + 1 !! (Note: Though it behaves like a line you have to consider the Domain of the ORIGINAL function, so when x = 1 you have a blank point in the graph, a removable discontinuity.)
2006-06-23 03:17:14
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answer #2
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answered by Edgardo A 1
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Zero divided by zero is a special case of a quotient whose denominator is zero. Normally, when zero is the denominator, the solution is undefined: for example, 7/0 is undefined since there is no number by which you might multiply zero in order to obtain a product of seven. Since zero multiplied by any number results in a product of zero, however; 0/0 is an indeterminate form. If you aren't interested in taking further math courses, but would like a little more information on this subject, you might want to try googling, " Indeterminate Forms, or Indeterminate Quotient Forms."
2006-06-23 05:02:08
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answer #3
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answered by tom d 2
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You are all wrong, 0 / 0 is indeterminate (which is not the same as undefined). An indeterminate form is an algebraic expression whose limit cannot be evaluated by substituting the limits of the subexpressions (i.e. limit as a->0 and b->0 of a/b can't be determined). Undefined is where expressions have no meaningful or sensible output.
Anything else divided by zero is infinity. An easy way to figure this out is looking at a graph of the limit as b->0 of a/b. As b approaches 0 the line goes to infinity.
2006-06-23 04:17:00
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answer #4
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answered by Nate 3
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The answer would be indeterminate because any value could be an answer.
For example, if 0/0=5, then 5 x 0 = 0 which is true. If 0/0=20, then 20 x 0 = 0.
2006-06-28 18:26:13
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answer #5
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answered by Anonymous
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Undefined.
Any number (including zero) divided by zero (n/0) is undefined.
2006-06-23 03:06:03
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answer #6
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answered by Neo_Apocalypse 3
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Numerator/ Denominator.....anything Except 0, divided by 0 is undefined only, because 0 in the denom. multiplied by anything will not get u that number in the numerator.....
.... But if the Numerotor itself is 0 and denominator is also 0, its not undefined but its a set if infinity.... as the denominator 0 multiplied by anything will give u the numerator.... So the ans. is infinite... covering all the Real and Complex numbers too.
2006-06-23 04:04:32
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answer #7
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answered by tapan 1
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Let's try to answer this. Let 0/0 = n, and we are trying to solve for it. Multiply both sides by 0 to get 0=0, which is obviously true! So it can be ANY number:
Since 0 = 0x3, 0/0=3
Since 0 = 0x4, 0/0=4
Since 0 = 0x5, 0/0=5
2006-06-23 05:53:32
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answer #8
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answered by vishalarul 2
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Anything divided by the number zero is termed "undefined", as you can't determine how many times nothing will go into something.
2006-06-23 03:04:55
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answer #9
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answered by Anonymous
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people who say 0/0=infinity are incorrect. the value of infinity isn't common. in spite of the indisputable fact that something divided by utilising 0 leads to an undefined volume which basically has a tendency to infinity.
2016-12-09 00:35:26
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answer #10
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answered by Anonymous
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The answer is undefined.You cannot define anything by dividing a number by zero.
2006-06-23 03:05:58
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answer #11
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answered by Wolverine 3
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