PLEASE: Algebra Help 2x^2-2y^2/-2x^2+2xy / (x^2+xy)?

Question

It reads 2x^2 minus 2y^2 over -2x^2 plus 2xy divided by (x^2+xy)

the answer is BETWEEN:

a. 2/3x

OR

b. -1/x^2

pLEASE nO gUESSES!

Divide the problem.

Answer 1

2x^2 - 2y^2 = 2(x^2 -y^2) = 2(x-y)(x+y)
-2x^2 + 2xy = -2x(x-y)
x^2 + xy = x(x+y)
2(x-y)(x+y)/[-2x(x -y)]/[x(x+y)]
= 2(x-y)(x+y)/[-2x(x-y)(x)(x+y)]
= -1/x^2

Answer 2

hi. i'm a intense college arithmetic instructor and professor and that i've got your answer. Alot of human beings get at a loss for words with the diverse divisions. yet think of of it as 10 divided by potential of 5 divided by potential of two (10/5/2) = a million. So whilst there are 2 demoninators all you do it multiply them. as a result (2 Xsqrd - 2 Ysqrd) / (-2 Xsqrd + 2XY) / (X sqrd + XY) = (2 Xsqrd - 2 Ysqrd) / (-2 Xsqrd + 2XY) * (X sqrd + XY). So initiate simplifying: 2(X+Y)*(X-Y) / (-2X * (X-Y) * X * (X+Y)) ====== do some cancelling and you get (-a million/Xsqrd). that is as uncomplicated as that: answer B.

Answer 3

[2x^2 - 2y^2] / [-2x^2 + 2xy] / [x^2 + xy]
= [2 (x^2 - y^2)] / [2 (xy - x^2)] / [x^2 + xy]
= (x^2 - y^2) / (xy - x^2) / (x^2 + xy)
= (x - y) (x + y) / (x) (y - x) / (x) (x + y)
= (-1) (x + y) / (x) / (x) (x + y)
= (-1) (x + y)/ 1 / (x + y)
= (-1) (x + y) (x + y) / 1
= (-1) (x^2 + 2xy + y^2)
= -x^2 - 2xy - y^2

Answer 4

The expression=2[x^2-y^2]/2[-x^2+xy]/[x^2+xy]
= [x^2-y^2]*[x^2+xy]/[-[x^2-xy]]
=[x^4-x^2y^2+x^3y-xy^3]/-[x^2-xy]
=[x^^3[x+y]-xy^2[x+y]]/-[x^2-xy]
=[x+y]*[x^3-xy^2]/-[x^2-xy]
=[x+y]*x[x^2-y^2]/-x[x-y]
=[x+y]*[x+y]*[x-y]/-x[x-y]
=[x+y]*[x+y]/-x
=x^2+y^2+2xy/-x
= -x-y^2/x-2y

Answer 5

Wait, you want people to do this for you? After the neocon speech you emailed me?

Personally, I think you should do your own homework. This is simple math, isnt it?