how do you do this? y=x2-5x+3?

Question

HOW DO YOU DO THiS???

Answer 1

x= -b +/- square root of b2 - 4ac all over 2a
so the answer is x=-.7 and x=4.3

Answer 2

there are 2 ways to do this;
you may (if u have luxury) plot graph and then do this
plot the graph and then solve it
or
take y = 0
which means
x^2 - 5x + 3 = 0
again u have 2 options now either use the quadtratic formula or factorize
for this option quadratic formula is the most sensible option

x = (-b +or - root (b^2 - 4ac)) / 2a
--> = (-5 + or - root(5^2 - 4(1)(3))) / 2(1)
--> = (-5 + or - root (13)) / 2
--> = (-5 +or - 3.60) / 2
--> = (-5 + 3.6) / 2 = (-5 - 3.6) / 2
--> = -1.4 / 2 = -8.6 / 2
--> = -0.7 = -4.3

x = -0.7 , -4.3

Answer 3

Are you sure you have the right equation? There are no whole number factors of 3 that will add up to 5....

If the equation was say y=x2-4x+3 then y = (x-1)(x-3)

Answer 4

If you want to graph it, use the vertex (5/2, -13/4) and use the points (0, 3) and (5,3).

If you want solutions to x^2-5x+3=0, complete the square:
(x-5/2)^2 - 13/4 = 0
(x-5/2)^2 = 13/4
x-5/2 = +or- sqrt(13)/2
x = [5 +or- (sqrt13)]/2

Answer 5

i know something simpler than what others had answer to you, you equation is
y=x^2-5x+3

you can give values to x or y. the most easy ones are 0

we are going to start with the x, so substitute it with 0 and your new equation is

y=(0)^2-5(0)+3

and then solve it. so they cancel because the multiplication gives 0, so your answer is

y=3, and your x=0. that's a point in a parabola

hope this help, i think you just wanted a point because you didn't explain your self.

Answer 6

I am not for sure... But I think like this..

y= x times 2 minus 5x plus 3... So I think the answer would be

xsquared-5+3...

not for sure tho... not the smartest at math

Answer 7

X = 5 +/- squareroot of 13 all divided by 2

Answer 8

x3 + 3 x2 - 5x + 4 by utilising x + one million? long branch: divide the main suitable term (x^3) of the numerator by utilising the 1st term (x) of the denominator x^3/x=x^2 then multiply that by utilising the great denominator x^2(x+one million)=x^3+2x subtract x^2-5x+4 repeat x^2/x=x x(x+one million)=x^2+x subtract -6x+4 -6x/x= -6 -6(x+one million)= -6x-6 subtract 10 something is 10/(x+one million)

Answer 9

does y = 0 ??

Answer 10

you need to factor them out

instead of having it in an x^2 + x + 1 format, you need to put it in the (x+1)(x-1) format...so just make sure when you have it in the two parenthesis you FOIL them out and get your original answer
let's pretend (x+1)(x-1) is your actual answer, you make each part = to zero and then solve

x+1=0 x-1=0
x=-1 x=1


and that is how you find the answer

Answer 11

this is solved using a formula: the roots for any equation of this kind eg. ax^2 + bx + c are : (-b + (b^2 - 4ac)^(1/2))/ 2a and (-b - (b^2 - 4ac)^(1/2))/ 2a don't worry it's easy...so for this one the answer would be: (5 + (13) ^ 0.5)/2 and (5- (13) ^ 0.5 )/2