what you have is something like
a(b+c)
the solution is
ab+ac
(x^3)(2x^-2)+(x^3)(4x)
now to multiply x^a * x^b you get x^(a+b)
2x^((3+(-2))+4x^(3+1)
2x+4x^4
2006-06-22 14:07:13
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answer #1
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answered by bequalming 5
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x^3(2x^(-2)+4x) = 2x+4x^4
This is a question that requires simple distributive law and exponent law. x^3 * 2x^(-2) = 2x, since when multiplying exponents with the same base you would add the exponents ( ie. -2 + 3 = 1). Then,
x^3 * 4x = 4x^4 for the same reason (ie. 3+1=4).
2006-06-22 15:51:14
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answer #2
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answered by Anonymous
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That equals 2x+4x^4 which equals to 2X(4X^3+1) thats about it for that one
2006-06-22 14:10:09
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answer #3
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answered by Neilman 5
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x^3(2x^-2+4x) = x^3 ( 2/x^2 +4x) = 2x + 4x^4
2006-06-22 14:12:29
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answer #4
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answered by lab_rat06 3
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(x^3)(2x^-2) + (x^3)((4x^1) =
2x^(3-2) + 4x^(3+1)=
2x^1 + 4x^4=
2x + 4x^4
It's the distributive property of multiplication to multiply out the terms, and then you add exponents when you multiply the terms.
2006-06-22 14:11:25
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answer #5
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answered by gameshowrecord 2
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x^3(2x^-2+4x)
4x^4 + 2x
2006-06-22 14:23:41
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answer #6
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answered by Mr Hex Vision 7
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how many x^2s can we've? from 3x we get no x^2s from -4x(x + 2) we get -4x^2 from -3(x^2 -x) we get -3x^2 so in entire we've (-4 + -3)x^2 = -7x^2 how many 'x's can we've? from 3x we get 3x from -4x(x + 2) we get -8x from -3(x^2 - x) we get (-3)(-x) = 3x so in entire we've (3 + -8 + 3)x = (6 - 8)x = -2x So the respond is A. -7x^2 - 2x IPOD: the unique cost became into extra beneficial than $one hundred sixty, in certainty 20% extra. to characteristic 20% to $one hundred sixty, i could multiply one hundred sixty * a million.20 = one hundred sixty + 32 = $192.
2017-01-02 04:02:54
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answer #7
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answered by ? 4
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x^3(2x -2 +4x)
2x^4 -2x^3 +4x^4
6x^4 -2x^3
24x^3 - 6x^2
72x^2 -12x
144x -12x
132x =0
x= -132
2006-06-22 14:26:22
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answer #8
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answered by Anonymous
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4x^4 + 2x
distribute and multiply
2006-06-22 16:16:01
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answer #9
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answered by jimbob 6
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No idea, I suck in Math! sorry da I can't help u wit da!
2006-06-22 14:05:57
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answer #10
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answered by Torque 1
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