Hi Guys I need help with simplifying?

Question

How do I solve 7 over 3x divided by x over 3
Next one: 2 1/3 - 3/4

Answer 1

(7/(3x)) / (x/3)
(7/(3x)) * (3/x)
21/(3x^2)
7/x^2

But if you meant

((7/3)x)/(x/3)
((7x)/3)*(3/x)
(21x)/(3x)
ANS : 7

-------------------------------

2 1/3 - 3/4
2 1/3 = (7/3)

(7/3) - (3/4)
Multiply everything by 12
(28 - 9)/12
(19/12) or 1 (7/12)

Answer 2

Is this homework?

7 over 3x divided by x over 3.
Invert the bottom fraction and multiply.
So it becomes 7/3x * 3/x, which simplifies to 7/x^2 (7 over x-squared).

2 1/3 - 3/4
2 1/3 is 7/3 or 28/12
3/4 is 9/12
28/12 - 9/12 = 19/12 = 1 7/12

Answer 3

7/3x / x/3

when you divide fractions you take the reciprocal of the second fraction and multiply

so now you have 7/3x * 3/x

now solve left to right top to bottom

21/3x^2

now simplify the top and bottom can be divided by three so you have
7/x^2

second one...you need to convert mixed numbers to improper fractions so you have
3*2+1=7

7/3-3/4

now you need common denominators which in this case is 12

so multiply the numerator and denominator of 7/3 by 4 and multiply the numerator and denominator of 3/4 by 3

so you have 28/12-9/12



so now you have 19/12

now put back into a mixed number 19/12=1 with a remainder of 7

so you have 1 7/12

check ya later ♥

Answer 4

A)

7 / 3x
______
x / 3 = 7 / 3x * 3 / x = 21 / 3x 2

= 21 / 6x

= 21 /1
________
1 / 6x

=21 / 1 * 6x / 1 = 126 x = 0; x =126

B)

2 1/3
- 3/4
=7 / 3
- 3/4
=21 /12
- 9/12
= 12 / 12
= 1

Answer 5

[7 / 3x] / [x / 3]
= [7 / 3x] * [3 / x]
= [7 * 3] / [3x * x]
= 21 / 3x^2
= 7 / x^2

2 1/3 - 3/4
= 7/3 - 3/4
= 28/12 - 9/12
= 17/12

Answer 6

7/3x over x/3 is equal to 7/3x times 3/x

Answer 7

the answer to the first one is 7 and the next one is 1

Answer 8

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