Let's say you have the following:
A 410 gram soccer ball is sitting on the ground. Someone comes running up and drills it at an angle of 35 degrees with a force of 49N.
I can infer that this object would have an initial vertical acceleration of 68.57 m/s^2. Is there any way to determine how high this ball would go, only knowing force applied, mass, and weight?
2006-06-22 11:44:24 · 3 answers · asked by pgufs 3 in Science & Mathematics ➔ Physics
Draw a free-body diagram of the ball and examine it's accelerations - if you assume wind and air resistance are negligible and that the ball is accelerated straight up, then you're left with its initial acceleration (68.57 m/s^2) and gravity (9.8 m/s^2 if I remember correctly)
The ball will decelerate by 9.8 m/s every second, you can divide to find the amount of time the ball takes to reach its apogee (point of zero acceleration), then integrate the acceleration curve to find the velocity curve, which can be integrated again to find the distance traveled. I'm not sure it can be done without the calculus.
2006-06-22 12:15:36 · answer #1 · answered by Anonymous · 0⤊ 0⤋
No. You need to know the duration of the force. This will give you a velocity, which can then be used to find the projectiles path. if the force is only applied for a brief moment the ball will not go very far, the longer the force is applied the faster it goes and the further it will go.
2006-06-22 18:49:08 · answer #2 · answered by santacruzrc 2 · 0⤊ 0⤋
Paul is close but you need to take into account that force is a vector and therefore it doesn't slow at 9.8m/s^2 be is accelerated down, which has nothing to do with over. Pay attention to your directions.
2006-06-22 19:30:42 · answer #3 · answered by satanorsanta 3 · 0⤊ 0⤋