Algebra Help: 2x^2-2y^2/-2x^2+2xy / (x^2+xy)?

Question

Divide

It reads 2x^2 minus 2y^2 over -2x^2 plus 2xy divided by (x^2+xy)

Answer 1

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Answer 2

This is a complex fraction. So you have to multiply by the recipricol of x^2+xy (the recepricol is 1/(x^2+xy)

2x^2-2y^2/-2x^2+2xy times 1/x^2+xy

When you multiply them together you should get:

(2x^2 - 2y^2)/(-2x^4-2x^3y+2x^3y+2x^2y^2)

I'm really not sure if this is right or what to do next.

Answer 3

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