First, find the slope of the line on which the two points lie:
m = (2 - 5) / (4 - 2) = -3 / 2 = -1.5
A line perpendicular to a line with slope m will have a slope -1/m
In this case, m(perpendicular) = 2/3
2006-06-22 10:22:10
·
answer #1
·
answered by jimbob 6
·
1⤊
0⤋
the slope of a line is y2-y1/x2-x1
=5-2/2-4
=3/-2 that syour slop
the perpendicular is 2/3
2006-06-29 00:48:00
·
answer #2
·
answered by ilovefridays 2
·
0⤊
0⤋
The sloope of a line is definded as:
(x1- x2)/(y1-y2) = (2-4)/(5-2) = -2/3
The slopes of two perpendicular lines m1 and m2 are related as follws:
m1m2 = -1,
implies m2 = -1/m1 = -1/(-2/3) = 3/2
2006-06-22 15:56:38
·
answer #3
·
answered by hackmaster_sk 3
·
0⤊
0⤋
slope is 2/3 of the perpendicular line to {(2,5)(4,2)}.
2006-06-22 15:55:37
·
answer #4
·
answered by Sree Y 1
·
0⤊
0⤋
the negative recrepical to the slope of the line
2006-06-22 17:05:27
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
figure it out by doing
(y2-y1)
divided by
(x2-x1)
thats ur slope
2006-06-22 15:54:49
·
answer #6
·
answered by im so unique 2
·
0⤊
0⤋