if a radius of a circle is 6, what is the area of half the circle?

Answer 1

it's pi x 18

because

r = 6

and aera is pi x r^2
so 1/2 the area will be 1/2 x pi x r^2

which is 1/2 x pi x 6^2

which is 1/2 x pi x 36

which is 18 x pi or approx 56.55

Answer 2

A = pi * r^2 = pi * 6^2 = 36pi

So area of half the circle = 36pi / 2 = 18pi = 56.55

Answer 3

if that is INSCRIBED then the radius is going from the middle of the circle to the nook of the sq.. this potential the diagonal of the sq. is two*radius = 12. The sq. is two 40 5-40 5-ninety triangles making the hypotenuse = x*sqrt(2) So the hypotenuse/x*sqrt(2) = section length of sq.. component to sq. = section length squared So then the respond = A = ((2*Radius)/sqrt(2)) ^2 = 2*radius^2

Answer 4

Area of a circle is Pi*r^2

Area = Pi*6^2
Area = Pi*36
Area = 3.14*36
Area = 113.04 --> Area of the whole circle
Area / 2 = 113.04 / 2 --> Area of the whole circle / 2
56.52 --> Area of the HALF circle

So, your answer is 56.52

Good luck :)

Answer 5

The area is pi*r^2 = 36pi. Half the area is 18pi.

Answer 6

A = Pi * r^2
A of half circle = (pi * r^2)/2
Ah = (pi * 6^2)/2
Ah = (36pi)/2
Ah = 18pi

Area of half the circle is about 56.55

Answer 7

6 squared, multiply by pi and divide by 2. (DON'T multiply 6 by pi and then square it, lol)

Try typing this into Google:

pi*6*6/2

Answer 8

well area of half circle is 18pie=18*3.14.

Answer 9

multiply six times pi. Square that result. Divide by two. That's HOW you do it. Now, YOU do it.

A = (pi x R) squared.

Answer 10

sq root of 18