Pure covalent or polar covalent?
2006-06-22 05:21:51 · 5 answers · asked by mrkittypong 5 in Science & Mathematics ➔ Chemistry
As far as I know, N and Br can form:
- a bromonium nitride R2N-...Br+:
result of organic nitride reacting with dibromide, where R = organic radical.
I think this kind of compound is similar to what is called chloramine ( R2N-Cl), so the N-Br bond would be a polar covalent bond (not a pure ionic bond because not a pure salt, nor a pure covalent bond.). I would say it is a covalent bond strongly polarised;
- an ammonium bromide R4N+...Br- : ionic bond (salt), not covalent at all.
2006-06-22 05:49:49 · answer #1 · answered by Axel ∇ 5 · 0⤊ 0⤋
The bond between N and Br would be surely covalent bond.
The electronegativity of Br is 3 and N is 2.8 according to Pauling scale.
3 Bromine atom would form a covalent bond with nitrogen.
2006-06-22 05:47:00 · answer #2 · answered by Zohaib H 2 · 0⤊ 0⤋
Covalent
2006-06-29 04:15:22 · answer #3 · answered by Me 2 · 0⤊ 0⤋
polar covalent, since nitrogen has a non bonding site, the 3 bromines would pull nitrogen downward causing an unbalanced pulling resulting in a polar bond
2006-06-22 05:27:05 · answer #4 · answered by aaa 1 · 0⤊ 0⤋
The larger the absolute difference in electronegativity between two atoms, the more polar that bond is. The difference between 3.0 and 2.8 is not that great.
2006-06-22 05:30:40 · answer #5 · answered by Steven A 3 · 0⤊ 0⤋