trigonometry
2006-06-22 04:30:57 · 10 answers · asked by fun2sh 2 in Science & Mathematics ➔ Mathematics
It depends on the distance the bird is from the person. The bird could be at 60 degrees from him, and be just a few inches above him.
2006-06-22 04:33:34 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The only way to tell this is if you knew how far away the bird was or how far away from the building you would have to be to be directly under the bird. (Use an umbrella if you see anything coming.)
Trig needs at least one length of a triangle and the length of one of the sides to complete all the other sides of the triangle.
2006-06-22 11:40:00 · answer #2 · answered by eric l 6 · 0⤊ 0⤋
Depends on how far the bird is. If the bird is right next to the viewer, the bird is also at 25m.
2006-06-22 11:37:27 · answer #3 · answered by Thomas F 3 · 0⤊ 0⤋
If a2 = b2 = c2, your vision squared would equal the height of the building multiplied by the trajectory. So, you would have the following
60(60) = (25)(25) * b2
3600 = 500b2
36 = 5b2
36/5 = b2
b, therefore, equals the square root of 36/5 (or 7.2m)
2006-06-22 11:35:05 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Cos 60 = 25m/hypoteneuse.....cross multiply....hcos60=25 25/cos60 which equals 50 according to my calculator
2006-06-22 11:35:52 · answer #5 · answered by jenn 4 · 0⤊ 0⤋
You also need to know if it is a 60 degree angle of depression or elevation.
2006-06-22 11:37:13 · answer #6 · answered by KHB 2 · 0⤊ 0⤋
Uhh.. he looking up or down? How tall is the person? How far is the bird from him?
2006-06-22 11:36:38 · answer #7 · answered by brand_new_monkey 6 · 0⤊ 0⤋
not enough information in question, need to know the distance between him and the bird.
2006-06-22 11:33:40 · answer #8 · answered by CRAZYDEADMOTH 3 · 0⤊ 0⤋
just figure out what kind of bird it is and figure it out from there... that would be a hell of alot easier
2006-06-22 11:33:51 · answer #9 · answered by Grin Reeper 5 · 0⤊ 0⤋
25mplus the height of the person while rasing his hands
2006-06-22 11:34:57 · answer #10 · answered by Anonymous · 0⤊ 0⤋