i just want to know on what basis did moeller make his diagram and how come there is no 2d or 1p or 3f orbital?
2006-06-22 03:39:22 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Orbitals are solutions to the schrodinger wave equation, quantum mechanics, taking into account translation, number, and rotation, letter. The rotational levels, s p d f, are from the symmetry of the solutions. With lower levels of translational energy the higher symmetries do not exist.
see the source from "Solution of Schrödinger equation: Overview of results" and down for a true mathematical explaination.
2006-06-22 12:24:18 · answer #1 · answered by satanorsanta 3 · 1⤊ 0⤋
Moeller Diagram
2016-12-11 17:38:28 · answer #2 · answered by Anonymous · 0⤊ 1⤋
each shell of electrons can have only a certain number of subshells. I think this comes out of solutions of the wave equations. So, the first shell (n=1) can have only 1 subshell which contains only one orbital (the s orbital). The second shell (n=2) can have only 2 subshells (s and p), the third shell can have only 3 subshells (s, p and d), and so on. The possible values of the 3 main quantum numbers dictate how many and what kinds of orbitals can exist in any particular shell.
2006-06-22 03:48:17 · answer #3 · answered by hcbiochem 7 · 1⤊ 0⤋
it all comes down to how many electrons a given electron has. based on that it tells how many shells are possible. the 2d, 1p, and 3f are mathmatically impossible due to quantum number theory.
2006-06-22 04:24:24 · answer #4 · answered by shiara_blade 6 · 0⤊ 0⤋