Deterimne the derivative of f(x)=(3x-2)(4x^3-x^2+1)
2006-06-21 15:40:12 · 7 answers · asked by mee c 1 in Science & Mathematics ➔ Mathematics
(3x-2)(12x^2-2) + (4x^3-x^2+1)(3)
That is the un-simplified answer
2006-06-21 15:47:44 · answer #1 · answered by ali 1 · 0⤊ 0⤋
6
2006-06-21 15:42:56 · answer #2 · answered by jc20155 4 · 0⤊ 0⤋
(d/dx)(f(x) * g(x)) = f'(x)*g(x) + f(x)*g(x)'
f(x) = (3x - 2)(4x^3 - x^2 + 1)
(3x - 2)'(4x^3 - x^2 + 1) + (3x - 2)(4x^3 - x^2 + 1)'
3(4x^3 - x^2 + 1) + (3x - 2)(12x^2 - 2x)
12x^3 - 3x^2 + 3 + (36x^3 - 6x^2 - 24x^2 + 4x)
12x^3 - 3x^2 + 3 + (36x^3 - 30x^2 + 4x)
12x^3 - 3x^2 + 3 + 36x^3 - 30x^2 + 4x
48x^3 - 33x^2 + 4x + 3
ANS : f'(x) = 48x^3 - 33x^2 + 4x + 3
2006-06-21 17:27:03 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
Take it from a math major :o)
48x³ - 33x² - 4x + 3
2006-06-22 03:28:45 · answer #4 · answered by jtweety614 2 · 0⤊ 0⤋
f(x)= 3x(4x^3-x^2+1)-2(4x^3-x^2+1)
= 12x^4-3x^3+3x-8x^3+2x^2-2
derivative is 48x^3-9x^2+3-24x^2+4x
=48x^3-33x^2+4x+3
2006-06-21 16:37:21 · answer #5 · answered by Naren 1 · 0⤊ 0⤋
12x^4-3x^3+3x-8x^3+2x^2-2
=12x^4-11x^3+3x-2
y'=48x^3-33x^2+3
2006-06-21 16:01:20 · answer #6 · answered by Anonymous · 0⤊ 0⤋
ummmmmmmmmmmm have you tried a calculator
2006-06-21 15:43:23 · answer #7 · answered by cameron 1 · 0⤊ 0⤋