2006-06-21 11:00:09 · 6 answers · asked by Hydro2e 1 in Science & Mathematics ➔ Physics
That would depend on the voltage. Current = Watts / Volts
A couple of examples:
110V - 90.9 Amps
220V - 45.45 Amps
240V - 41.67 Amps
440V - 22.7 Amps
10,000V - 1 Amp
2006-06-21 11:06:04 · answer #1 · answered by davidmi711 7 · 0⤊ 0⤋
Take the wattage and divide it by the voltage in order to the the amperage. In theory it could be an infinitely small amount of voltage and an infinitely large current.
However, when you get below 110 volts for a 10 KW power source, the conductor becomes so wide and bulky it is impractical to use. You would have wires as thick as a bath mat and thinner than tin foil at some point. It is for this reason I would say 90 amps at 110 volts. It would be enough to kill.
2006-06-21 19:04:15 · answer #2 · answered by eric l 6 · 0⤊ 0⤋
The maximum amperage is limited by the internal resistance of the generator. All sources of power have some internal resistance.
For example, if you have an internal resistance of 1 ohm, using the formula 10 kW = I^2 * R would yield a maximum current of 100 amps because you can never reduce the resistance in any circuit below the internal resistance of 10 ohms.
2006-06-21 19:49:04 · answer #3 · answered by volume_watcher 3 · 0⤊ 0⤋
Power= Amperage times Voltage
so 10,000Watts = Amp times the amount of voltage used. it depends on the voltage used
2006-06-21 20:25:50 · answer #4 · answered by cuckoo meister 3 · 0⤊ 0⤋
The internal resistance of the system must be known to tell the max ampere.
2006-06-21 23:07:28 · answer #5 · answered by Pearlsawme 7 · 0⤊ 0⤋
Yep. Max would be infinate at zero volts.
2006-06-21 18:09:05 · answer #6 · answered by Craig D 2 · 0⤊ 0⤋