i just have this week and next week..........to finish this class......if i can pass with at least a C this would be good...............
2006-06-21 08:20:09 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
An x-intercept occurs where y = 0, so plug in 0 for y.
x^2 + x - 6 = 0
Factor the quadratic equation (reverse FOIL)
(x + 3)(x - 2) = 0
x = 2, -3
2006-06-21 09:23:57 · answer #1 · answered by jimbob 6 · 2⤊ 0⤋
you have to find the factors of the right hand side...you have
y = x^2 + 1x - 6
So you need two numbers that ADD to 1 and MULTIPLY to -6. In this case they are 3 and -2, so the factors are:
y = (x + 3)(x - 2)
The x-intercept is where y = 0, so (x+3)(x-2) must equal 0. This can only happen if either (x+3) or (x-2) is 0. So x must be -3, or 2.
2006-06-21 15:24:39 · answer #2 · answered by -j. 7 · 0⤊ 0⤋
Make the equation equal to zero, then factor.
0 = x^2 + x - 6
0 = (x-2)(x+3)
x = 2 or -3
2006-06-21 15:54:17 · answer #3 · answered by trancevanbuuren 3 · 0⤊ 0⤋
Using a graphing calculator would be easy if you are allowed to do so. Also, there is a very useful formula to use to find the x-intercepts for any quadratic:
first, your equation has to be in the y=ax^2+bx+c format, which it is. So, for you, a=1, b=1, and c=-6
To find the x-intercept,
x=-b+sqrt(b^2-4ac)/2a
and
x=-b-sqrt(b^2-4ac)/2a
2006-06-21 15:38:17 · answer #4 · answered by q2003 4 · 0⤊ 0⤋
factor to get (x+3)(x-2) x intercepts are then -3 and 2
2006-06-21 15:23:10 · answer #5 · answered by Aaron G 2 · 0⤊ 0⤋
You will want to factor into two binomials (x-a)(x+b) See if you can figure out what a and b are. The intercepts are (+a) and (-b).
2006-06-21 15:23:04 · answer #6 · answered by johndersel 3 · 0⤊ 0⤋
y = x^2 + x - 6
(x + 3)(x - 2) = 0
x = -3 or 2
2006-06-21 16:28:24 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋