Reduce to lowest terms.
Best answer will be selected 2morrow!
2006-06-21 06:31:02 · 9 answers · asked by Brandon ツ 3 in Science & Mathematics ➔ Mathematics
14x^4y^4/18x^2y^5
Since x^1 and y^1 must remain in any reduction, at lowest terms this would be:
7x^3y/9xy^2
Read: seven x cubed y over nine x y squared
2006-06-21 06:48:36 · answer #1 · answered by ensign183 5 · 2⤊ 1⤋
Assuming there are () around everything after the /:
Just look at the pieces,
14/18 = 7/9.
x^4/x^2 = x^2
y^4/y^5 = 1/y or y^(-1)
So, your answer is: (7/9) x^2 y^(-1) or 7x^2/(9y)
2006-06-21 13:38:41 · answer #2 · answered by tbolling2 4 · 0⤊ 0⤋
7x^2/9y or (7x^2y^-1)/9
break it into terms
14x^4y^4/18x^2y^5
is the same as
(14/18)*(x^4/x^2)*(y^4/y^5)
so 14/18 = 7/9
x^4/x^2 = x^2/1 = x^2
y^4/y^5 = 1/y = y^-1
2006-06-21 13:34:14 · answer #3 · answered by CRAZYDEADMOTH 3 · 0⤊ 0⤋
14x^4*4y^4/18x^2*2y^5
when dividing exponents you just subtract the exponents from the same variable.
y-1
1/y*7/9x^2
7x^2/9y whoops i know what i did wrong sorry
check ya later â¥
2006-06-21 15:10:15 · answer #4 · answered by ♥ The One You Love To Hate♥ 7 · 0⤊ 0⤋
(14x^4y^4)/(18x^2y^5)
(14/18) * x^(4 - 2) * y^(4 - 5)
(7/9)x^2 * y^(-1)
ANS : (7x^2)/(9y)
2006-06-21 16:23:59 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
14x^2/9y
2006-06-21 13:35:30 · answer #6 · answered by ag_iitkgp 7 · 0⤊ 0⤋
Do your own homework.
2006-06-21 13:35:37 · answer #7 · answered by D-pig 4 · 0⤊ 0⤋
(7x^2) / (9y)
2006-06-21 16:42:45 · answer #8 · answered by jimbob 6 · 0⤊ 0⤋
(7x^2)/(9y)
2006-06-21 13:37:15 · answer #9 · answered by Anonymous · 0⤊ 0⤋